Recent content by Kenneth Blaney

Good one. The failure is in "0=1-1+1-1+1-1+..." which is actually a way of multiplying infinity and 0. This is an "indeterminate form" and so may not be strictly equal to 0. Consider lim x-> 0 of sin(x)*1/x. This limit is also 0*inf which can be converted to 0/0 so that we may apply...