Cheeze_Pavilion post=18.73797.815865 said:
Samirat post=18.73797.815847 said:
No, it doesn't say. Therefore, you have to assume the possibility that he did either. Assuming one is wrong. Assuming both is wrong. Therefore, our solution takes into account both. Yours is only if the first one is male.
Why? I didn't say we have to eliminate M/F and we can't eliminate F/M. I said we have to eliminate one and only one of M/F and F/M. That's how I assume the possibility that he did either--by eliminating one and only one.
+++++
Maybe if we start off with a better matrix:
Puppy That Serves as the Warrant For His Response/Other Puppy
M/M
M/F
F/M
F/F
Then he responds and says yes--there's at least one male.
So how can we leave any F's under the heading Puppy That Serves as the Warrant For His Response? If we leave any F's, that means he's lied to us, which we have no reason to assume from the word problem.
So, what if he uses the second puppy as the warrant for his response. Are you saying that invalidates Male Female? So you're crossing one off based on the fact that one or the other must have been male. It's an elegant argument, but ultimately incorrect.
Again, it assumes that we know the position of the male dog. You can't arbitrarily place it first. Because if the second one is male, the first one *must* be female. Otherwise, it would fall under the male male category. Right? If the first dog is male, the second one could be either female or male.
All right, let me go to the information difference.
You have 2 dogs, you know the first one is male. (Not this problem)
You have 2 dogs, you know one of them is male. (This problem)
Are you saying that this is the same problem? One contains more information, so how can you justify making the probability for them the same?
All right, do you recognize that in the coin toss analogy, placing one heads and flipping the other is incorrect? Compared to flipping both, and if one is heads, seeing if the other is also heads. The if statement corresponds to the question, "is one male." If neither is male, this isn't what happened in the problem, and you're free to reflip. Since the chances of each dog being male or female is 50 50, this is equivalent to a double coin toss. Inside the 75 percent sample space that represents the "yes" answer in the problem, you have twice as many pairs of one male one female as you do double male.