0=2, math inside.

[blackshark121]

First off, this particular proof is search bar approved, and does not contain division by zero.

cos[sup]2[/sup]x=1-sin[sup]2[/sup]x.........................Given
cos x = (1-sin[sup]2[/sup]x)[sup]1/2[/sup]................Square root each side.
1+ cos x = (1-sin[sup]2[/sup]x)[sup]1/2[/sup] + 1....Add one to each side
1 - 1 = (1-0)[sup]1/2[/sup] + 1..................Evaluate at x = pi (3.14159...)
0 = 1 + 1
0 = 2


So where is the error?

EDIT: I probably should expand, I am trying to find the error, I am not posing this as trivia.

EDIT2: Alright, I asked my calc professor, and he went about saying that I didn't restrict the domain, thus allowed square root problem. Thanks for the help. I also should mention that when evaluating cos pi or sin pi, you need to use radians, not degrees.

And to keep the topic going, what are some other fun math equations you can find?

 

[Amardor]

2 > 0.

/Thread Over

 

[Z of the Na'vi]

Math?

On the Escapist?

Wha? *has a brain lapse*

 

[SonicKoala]

0 = 2


So where is the error?

Right freaking there

 

[Toaster Hunter]

AAHHH!!! Numbers, brain on fire.

2 does not equal 0. I'm horrible at math and I figured that out.

 

[Asinine]

Sorry to spoil your fun, but
(1-(sin(pi))^2)^1/2 = 1 or -1 (the same goes for the root of any other number)
therefore the resultant equation may also be
1-1 = -1 + 1
which is simplified into 0 = 0.
now that makes more sense

 

[KillerH]

First off, this particular proof is search bar approved, and does not contain division by zero.

cos[sup]2[/sup]x=1-sin[sup]2[/sup]x.........................Given
cos x = (1-sin[sup]2[/sup]x)[sup]1/2[/sup]................Square root each side.
1+ cos x = (1-sin[sup]2[/sup]x)[sup]1/2[/sup] + 1....Add one to each side
1 - 1 = (1-0)[sup]1/2[/sup] + 1..................Evaluate at x = pi (3.14159...)
0 = 1 + 1
0 = 2


So where is the error?

EDIT: I probably should expand, I am trying to find the error, I am not posing this as trivia.

I think it's a simple process issue. It should be
(cos[sup]2[/sup]x)[sup]1/2[/sup] = (1-sin[sup]2[/sup]x)[sup]1/2[/sup] using that process (instead of just dropping the [sup]2[/sup] on the cos) you will get 1-1 = -1+1 or 0=0

EDIT:

Sorry to spoil your fun, but
(1-(sin(pi))^2)^1/2 = 1 or -1 (the same goes for the root of any other number)
therefore the resultant equation may also be
1-1 = -1 + 1
which is simplified into 0 = 0.
now that makes more sense

this as well

 

[DazZ.]

Can't name variables as numbers, 0=2 would give you a syntax error.

 

[SnootyEnglishman]

0=2....That is your error.

You'll need something like x y or z =2 not a number equaling a number that makes no sense

 

[USSR]

Lets not start this again.

Almost as bad as the infamous 0.9 repeating = 1 thread.

 

[ssgt splatter]

UGH! My brain hurts. I already have a hard enough time with Int. Alg. I don't need to see Trig or Cal or whatever the hell this is.

 

[Jamface]

Lets not start this again.

Almost as bad as the infamous 0.9 repeating = 1 thread.

I hate whoever decided infinite 0.9 = 1. By that logic you could say that every number is the same.

 

[GRoXERs]

1 - 1 = (1-0)[sup]1/2[/sup] + 1..................Evaluate at x = pi (3.14159...)
So where is the error?

Oh never mind I fail at math.

Sorry to spoil your fun, but
(1-(sin(pi))^2)^1/2 = 1 or -1 (the same goes for the root of any other number)
therefore the resultant equation may also be
1-1 = -1 + 1
which is simplified into 0 = 0.
now that makes more sense

Yeah, this.

 

[Woodsey]

Whilst I have no idea what the explanation was (maths never looks understandable on a computer) I can tell you that 0 isn't equal to 2.

 

[ninjapenguin981]

The error is here

cos x

When you rooted the cos^2 x then you should have root x still.

 

[Armored Prayer]

Math!?

Back away not today.

 

[Rand-m]

Call me crazy, but unless my calculator shat itself, cos(pi) does not equal -1, and Sin^2(pi) does not equal 0.

 

[Red Right Hand]

First off, this particular proof is search bar approved, and does not contain division by zero.

cos[sup]2[/sup]x=1-sin[sup]2[/sup]x.........................Given
cos x = (1-sin[sup]2[/sup]x)[sup]1/2[/sup]................Square root each side.

It don't think it works like that, you can't just take square root of the other side and get rid of the cos[sup]2[/sup]x.
Subbing in pi gives you

-1 =/= 1

Therefore cos x =/= (1-sin[sup]2[/sup]x)[sup]1/2[/sup]

 

[MR T3D]

when evaluating the square root, there is a positive AND negative answer in theory, therefore you evaluated one of the square roots incorrectly.
specificially,
sqrt1 = +1 OR -1
in this case it must be -1 for the equation.