DaBigCheez said:
5. Condense the right side:
2x = x
6. Divide through by x:
2 = 1
I stripped out everything except for the two really bad steps. Five is the one that's the tip off for your proof being wrong.
There are only three ways for 2x to be equal to x.
1. Give up the identity property of X. Thus x =/= x. It solves step five, but makes step six impossible.
2. Give up the identity property of the real numbers (it does happen in some higher level math). It solves step five, and step six, but doesn't allow for your conclusion to make any sense, since your proof can no longer support the proposition that 1 = 1, or that 2 = 2.
3. Have x = 0 or infinity.
Ignoring any of the steps it took to get you to 2x = x (and there are other earlier errors) that's the most staggering. There is no number for x (assuming constant values for 1 and 2) which can yield a true response to 2x = x. It can't happen using standard math.
My best guess is that you're dropping the identity property of x, since you do mess with it in step four, but that would make it impossible to divide both sides by x as a way to remove it.
DaBigCheez said:
4. As these are the same equation, their derivative must be the same. Take the derivative of both sides:
d(x^2)/dx = d((x + x + x + ...) x times)/dx
2x = (1 + 1 + 1 + ...) x times.
This is the other big time issue I see. Even ignoring that dx/dx wouldn't actually yield a derivative in any real way (since you'd be taking the change in x over the change in x, which wouldn't offer any derivative other than one), you don't properly derive the right side.
You can't make x*x into discrete terms simply by dividing them with words. Your method would be akin to saying that dy/dx of X^2 is the same as X(X) or x times x. Since the derivative of x = 1, the derivative of x^2 is 1, since 1(1) is 1. Even if your logic worked, you forget to derive both parts of the right side. You don't derive the "x times" portion itself, which would yield (following your logic) 2x = (1 + 1 + 1 + ...) 1 time. Either derive fully, or not at all.