You know what, I just actually checked it and you're right. I suppose the guy who maintains the limerick DB isn't particularly good at calculus, but I do suppose it's my fault for not checking it first.Iron Lightning said:My calculus is a bit rusty, but I'm pretty sure that a definite integral going from a to b of f(x) is equal to F(b)-F(a) or (in other words) the value of the integral at point b minus the value of the integral at point a. The fact that our answers do not agree shows that one of us is incorrect. I should also mention that because trigonometric functions are dependent on units, it is impossible to determine an answer without knowing the units used.mettle_edge said:To fill in the blank " the log of the cube root of 3"Iron Lightning said:int(Z^2)dz = (Z^3)/3mettle_edge said:Here's one for ya.
The integral of zee-squared dee zee,
From 1 to the cube root of 3,
Times the cosine,
Of 3 pi over 9,
Is ______________________
((cbrt(3)^3)/3)-((1^3)/3) = 2/3
(2/3)*cos((3*pi)/9) = 1/3
assuming you're using radians, if you're using degrees, then the answer is
0.666555319636
oooh, scary.
3^1/3
Put in whole integral form: (COS(3pi/9)) S z^2 dz= log(e^1/3)
1
I think...
It's still a well rhymed limerick though. Just wish it was right.