So.... How about a math question?

Recommended Videos

mettle_edge

New member
Aug 7, 2010
58
0
0
Iron Lightning said:
mettle_edge said:
Iron Lightning said:
mettle_edge said:
Here's one for ya.

The integral of zee-squared dee zee,
From 1 to the cube root of 3,
Times the cosine,
Of 3 pi over 9,
Is ______________________
int(Z^2)dz = (Z^3)/3
((cbrt(3)^3)/3)-((1^3)/3) = 2/3
(2/3)*cos((3*pi)/9) = 1/3
assuming you're using radians, if you're using degrees, then the answer is
0.666555319636

oooh, scary.
To fill in the blank " the log of the cube root of 3"
3^1/3
Put in whole integral form: (COS(3pi/9)) S z^2 dz= log(e^1/3)
1
I think...
My calculus is a bit rusty, but I'm pretty sure that a definite integral going from a to b of f(x) is equal to F(b)-F(a) or (in other words) the value of the integral at point b minus the value of the integral at point a. The fact that our answers do not agree shows that one of us is incorrect. I should also mention that because trigonometric functions are dependent on units, it is impossible to determine an answer without knowing the units used.
You know what, I just actually checked it and you're right. I suppose the guy who maintains the limerick DB isn't particularly good at calculus, but I do suppose it's my fault for not checking it first.

It's still a well rhymed limerick though. Just wish it was right.
 

SomeLameStuff

What type of steak are you?
Apr 26, 2009
4,291
0
0
MajorLandmark said:
What is the general solution to the differential equation:

2d^2y/dx^2 + 2dy/dx + 5y = 13sin(x)

Anyone who can do this I'd wager, has a degree. On that note, dont expect me to explain how to do it :p. I do have the answer though.
Oh hey just started this chapter in school like, 2 hours ago.

I'll be attempting that now.