subnetting fun

[Aralous]

Needed: 200 hosts
Network address: 5.0.0.0
Class: A
Default Subnet Mask: 255.0.0.0 / 11111111.00000000.00000000.00000000
Custom Subnet Mask: 255.255.255.0 / 11111111.11111111.11111111.00000000
Subnet Bits: 16
Total Subnets: 65,536
Host Bits: 8
Total Hosts: 256 (254 usable)

What is the Net ID and Broadcast address for the 2nd subnet?


If someone can explain to me how to figure this out I would be very grateful.

 

[Aralous]

No CCNA gurus on tonight? ><

 

[DefunctTheory]

Impossible to tell.

I'd need at least one of the IP address from the smaller range to tell.

EDIT: Whoops, misread.

Give me a second, I'm rusty.

EDIT:

IP Range: 5.0.1.0 - 5.0.1.255
Net ID: 5.0.1.0
Gateway: 5.0.1.1
Broadcast: 5.0.1.255
Usable IP Range: 5.0.1.2 - 5.0.1.254

And its a /24, not /16.

 

[c008644]

Host range 5.1.0.1 - 5.1.0.254
Broadcast 5.1.0.255
Subnet ID 5.1.0.0

 

[DefunctTheory]

Impossible to tell.

I'd need at least one of the IP address from the smaller range to tell.

EDIT: Whoops, misread.

Give me a second, I'm rusty.

EDIT:

IP Range: 5.0.1.0 - 5.0.1.255
Net ID: 5.0.1.0
Gateway: 5.0.1.1
Broadcast: 5.0.1.255
Usable IP Range: 5.0.1.2 - 5.0.1.254

And its a /24, not /16.

EDIT (Again):

How to do it.

The Subnet is a /24, so the first 24 bits are locked in. If we start from the bottom, that means the first will be 5.0.0.0. To move to the next subnet, you have to go to the next highest number INSIDE the subnet portion, which would be 00000001 (Or just 1). So the third subnet would be 00000010 (2) and so on.

The first available IP address is the NetID, ALWAYS. The second (+1) is the gateway. The LAST is the broadcast (Not necessarily going to be a 255).

edit: Weird, thought I was editing.