Serial Killer Round 39: Return of the Doubles Round (Cycle 12: We Have A Winner!)
- Thread starter CounterAttack
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@staika I have no fucking clue. 11?
Okay, I checked. It's 12, apparently. I musta missed one of them. If I remember right, those first four 0s are meaningless because it goes 0001, 0010, 0100, 1000 until 1111, then it goes to the second set.
Captcha: complex number
Seriously, it hasta be self-aware. Too many coincidences!
Okay, I checked. It's 12, apparently. I musta missed one of them. If I remember right, those first four 0s are meaningless because it goes 0001, 0010, 0100, 1000 until 1111, then it goes to the second set.
Captcha: complex number
Seriously, it hasta be self-aware. Too many coincidences!
@Staika
Zero to fifteen in binary, octal and hex-
0000, 0001, 0010, 0011, 0100, 0101, 0110, 0111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111.
0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F,
12 in decimal, 14 in Octal or D in Hex
Zero to fifteen in binary, octal and hex-
0000, 0001, 0010, 0011, 0100, 0101, 0110, 0111, 1000, 1001, 1010, 1011, 1100, 1101, 1110, 1111.
0, 1, 2, 3, 4, 5, 6, 7, 10, 11, 12, 13, 14, 15, 16, 17,
0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F,
Think of it like this
Decimal is broken up into segments equal to 10^(x-1), where 'x' is the number of digits away from the deicmal on the right.
So 1467 broken up is 1*10^3 + 4*10^2 + 6*10^1 + 7*10^0.
Binary works the same way, but with powers of 2 rather than power of 10. Because there is only 2 possible options before going onto the next power, the digits can only be represented by a 1 or 0.
So 1467 in binary is 11011111011 which is broken down into 1*2^10 + 1*2^9 + 0*2^8 + 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 +0*2^2 + 1*2^1 + 1*2^0.
Octal and Hex are a little bit more tricky, but at their core are the same.
With octal you take each group of 3 digits (starting from the right) and replace it with the number from 0-7 that it represents, so 1467 shows up in octal as 3373.
Hex is where you take a group of 4 digits(starting from the right.), and replace it with the number from 0-9 or A-F, with A-F replacing numbers greater than 9. So 1467 in Hex is 6FC.
Decimal is broken up into segments equal to 10^(x-1), where 'x' is the number of digits away from the deicmal on the right.
So 1467 broken up is 1*10^3 + 4*10^2 + 6*10^1 + 7*10^0.
Binary works the same way, but with powers of 2 rather than power of 10. Because there is only 2 possible options before going onto the next power, the digits can only be represented by a 1 or 0.
So 1467 in binary is 11011111011 which is broken down into 1*2^10 + 1*2^9 + 0*2^8 + 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 +0*2^2 + 1*2^1 + 1*2^0.
Octal and Hex are a little bit more tricky, but at their core are the same.
With octal you take each group of 3 digits (starting from the right) and replace it with the number from 0-7 that it represents, so 1467 shows up in octal as 3373.
Hex is where you take a group of 4 digits(starting from the right.), and replace it with the number from 0-9 or A-F, with A-F replacing numbers greater than 9. So 1467 in Hex is 6FC.
I REFUSE TO ALLOW THIS THREAD TO BE ABOUT LEARNING!
*unleashes swarm of rascally raccoons upon he unsuspecting students*
*unleashes swarm of rascally raccoons upon he unsuspecting students*
The way I do it is mostly addition and my teacher calls it the simple method. How it works is that each decimal place counts as a power of 2 and depending on if the number in the binary is 1 or 0 tells you whether to add it or not. So let's try 10010011
since there are 8 bits in this number we write out the 8 powers of 2 which are:
1
2
4
8
16
32
64
128
Now starting from the right of the binary number we would only add the ones that are '1' in the binary number. So it would be 1+2+16+128=147. so the decimal version of 10010011 would be 147 if I did my math right.
since there are 8 bits in this number we write out the 8 powers of 2 which are:
1
2
4
8
16
32
64
128
Now starting from the right of the binary number we would only add the ones that are '1' in the binary number. So it would be 1+2+16+128=147. so the decimal version of 10010011 would be 147 if I did my math right.
Edit: Man I'm a terrible teacher as I think this wouldn't make sense to other people :/
@Berenzen: No-one's been penalised for one post of advertising... but I note that your thread is on the front page of the forum. Surely such advertising would be unnecessary?