int(Z^2)dz = (Z^3)/3mettle_edge said:Here's one for ya.
The integral of zee-squared dee zee,
From 1 to the cube root of 3,
Times the cosine,
Of 3 pi over 9,
Is ______________________
((cbrt(3)^3)/3)-((1^3)/3) = 2/3
(2/3)*cos((3*pi)/9) = 1/3
Assuming that you're using radians, if you're using degrees then the answer is:
0.666555319636
oooh, scary.